A line passes through (5,3) with a slope of 3/5. Plot 3 points on this line

y=3/5*x, A(0,0), B(1,3/5), C(2,6/5)

Step-by-step explanation:

A(5,3)=(x1,y1)x1=5, y1=3

m=3/5

y-y1=m(x-x1)

y-3=3/5(x-5)

y-3=3/5*x-3/5*5

y-3=3/5*x - 3

y=3/5*x-3+3

y=3/5*x

x=0, y=3/5*x, y=3/5*0=0 A(0,0)

x=1, y=3/5*1=3/5 B(1,3/5)

x=2, y=3/5*2=6/5 C(2,6/5)

See below.

(I only answered the first one b/c the second log function doesn't really make sense, sorry!)

Step-by-step explanation:

1. f(x) = 5 ×

Plug in 5 points.

x = -2, f(x) =

x = -1, f(x) =

x = 0, f(x) = 5

x = 1, f(x) = 15

x = 2, f(x) = 45

2. Attached below.

3. Increasing

4. Domain: x = all real numbers

Range: f(x) > 0 (because the line never goes below the x-axis)