A line passes through the point (8, -3) and has a slope of 3/4 write an equation in slope intercept form

y = (3/4)x - 9

Step-by-step explanation:

The slope-intercept form of the equation of a straight line is y = mx + b.

Here we know x, y and m, but must find b.

Substituting 8 for x, -3 for y and 3/4 for m in the equation above results in:

-3 = (3/4)(8) + b, or (after multiplying all three terms by 4 to clear fractions):

-3 = 6 + b

Then b = -9, and the desired equation is     y = (3/4)x - 9

Take the equation and put it into ax² + bx + c = 0.

3x² + 4x - 6 = 0

a = 3
b = 4
c = -6

The quadratic formula is :

x = -b ± √b² - 4ac / 2a

Substitute the values.

x = -4 ± √4² - 4(3)(-6) / 2(3)

x = -4 ± √16 + 72 / 6

x = -4 ± √88 / 6

x = -4 ± 2√22 / 6

Simplify the equation by factoring out the 2.

x = -2 ± √22 / 3

Solutions :

x = -2 + √22 / 3

x = -2 - √22 / 3