A line that is parallel to y=-3x+2 and contains the point (3,-3)

y = -3x + 6

Step-by-step explanation:

Two lines that are parallel will have the same slope. All we need to do is find the new y-intercept.

-3 = -3(3) + b

-3 = -9 + b

6 = b

Now we can input the stuff we know and solved for back into the original formula [ y = mx + b ].

y = -3x + 6

Best of Luck!

A parallel line means our new line will have a slope equal to the original line.

The original line is in slope-intercept form, y = mx + b, where m is the slope and b is the value of the y-intercept. This tells us that the slope we want to use is m = -3

By using a slope of -3, with the given point (3,-4), we can now use the point-slope formula to find our new line.

Point-slope formula: y - y1 = m(x - x1) where m is the slope and the line passes through the point (x1,y1)

Combining our point and slope, we get:

y + 4 = -3(x - 3)

If we wish, we can rearrange this by distributing on the right hand side.

y + 4 = -3x + 9

We can then subtract 4 from both sides to get our answer in slope-intercept form

y + 4 - 4 = -3x + 9 - 4

y = -3x + 5

sorry for this

Step-by-step explanation:

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