A local sports team wants to estimate the average amount of time that spectators spend getting out of the parking garage after games. Find the minimum sample size required to estimate that average (in minutes) to within 5.0 minutes with 90% confidence if the population standard deviation was previously estimated to be 21.6 minutes.

The minimum sample size required to estimate that average is 51

Step-by-step explanation:

In order to calculate the minimum sample size required to estimate that average we would have to calculate the following formula:

minimum sample size required to estimate that average =(z∝/2σ/E)∧2

According to the given data we have the following:

z∝/2=1.645

E=5

σ=21.6

Therefore, minimum sample size required to estimate that average =(1.645*21.6/5)∧2

minimum sample size required to estimate that average =51

The minimum sample size required to estimate that average is 51

You need one equation for the physical nickels and dimes, which total to 21:

n+d=21

Secondly, you need one equation for the numerical value of those nickels and dimes. We know nickels are worth $0.05 and dime are worth $0.10:

.05n+.1d=1.70