Mathematics: A man invested 1000 rupees,split onto two schemes,at annual rates of interest 8% and 9%.After one year he got 875 rupees as interests from both. How much did he invest in each?

A man invested 1000 rupees,split onto two schemes,at

mrylenastewart

08.02.2022

Given :

Total amount, T = 10000 . ( It should not 1000 )

Annual rates of interest in both scheme is 8% and 9% .

After one year he got 875 rupees as interests from both.

To Find :

How much did he invest in each.

Solution :

Let, amount invested in 8% annual interest scheme is x.

So, amount in other scheme is 10000-x .

Now, sum of interest is equal to 875.

$\dfrac{x\times r_1 \times 1}{100}+\dfrac{(10000-x)\times r_2\times 1}{100}=875\\\\8x + 9(10000-x)=87500\\\\x = 90000-87500\\\\x = 2500$

Therefore, amount invested in 8% and 9% annual interest scheme is 2500 and 7500 rupees respectively.

Hence, this is the required solution.

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keke1871

29.04.2022

$512\ m^{3}$

Step-by-step explanation:

Volume of any cube equals a product of all the edge lengths. Since there are 3 edges:

$V = a^{3} = 8^{3} = 512\ m^{3}$

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