A manufacture of spark plugs how's it going producing less than 2% affective ones. Of the last 8000 spark plugs, 13 were defective. a. What is the experimental probability that the next sparkplug will be defective? b. Did the manufacture reach his goal? Explain.

P = 0.001625

yes, it did

Step-by-step explanation:

given data

affective ones = 2%

spark plugs = 8000

defective = 13

to find out

experimental probability that the next sparkplug will be defective and Did the mannufacturer reach its goal

solution

we know that there are 13 are defective out of 8000

so P = 13 ÷ 8000

P = 0.001625

so  that P( the next sparkplug will be defective) is = 0.001625

and

yes, we mannufacturer to reach goal

because 0.001625 < .02

So, the goal is reached as the experimental probability is less than 2%

Square Root of 41 to the nearest tenth, means to calculate the square root of 41 where the answer should only have one number after the decimal point.

Here are step-by-step instructions for how to get the square root of 41 to the nearest tenth:

Step 1: Calculate

We calculate the square root of 41 to be:

√41 = 6.40312423743285

Step 2: Reduce

Reduce the tail of the answer above to two numbers after the decimal point:

6.40

Step 3: Round

Round 6.40 so you only have one digit after the decimal point to get the

6.4

To check that the answer is correct, use your calculator to confirm that 6.42 is about 41.

Step-by-step explanation: