Mathematics: A mother who is 35 years old has two sons, one of whom is twice as old as the other. In 3 years the sum of all their ages will be 59 years. How old are the boys at present ?

A mother who is 35 years old has two sons, one of

Ответ:

skboy1050

30.01.2022

Mathematics

son2: 5

son1: 10

Step-by-step explanation:

2x (son1) + x (son2) + 35 (mother) + 3 (years)*3 (people) = 59

3x = 15

x = 5

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Ответ:

gutuerrezsebastian

30.01.2022

Mathematics

X= age of youngest son
2x = age of oldest son
in three years.
x + 3 + 2x + 3 + 35 + 3 = 59
3x + 35 + 9 = 59
3x + 44 = 59
3x = 15
x= 5
Therefore boys at present:
Youngest is 5 years old
Oldest is 10 years old

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Ответ:

cbrewer37

13.10.2022

Mathematics

100% / 4 is 25%
So she put 25% away and spent 75% of her allowance

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A mother who is 35 years old has two sons, one of whom is twice as old as the other. In 3 years the sum of all their ages will be 59 years. How old are the boys at present ?

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