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hannaho8714
10.08.2021 •
Mathematics
A movie theater has a seating capacity of 333. The theater charges $5.00 for children, $7.00 for students,
and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $
2422, How many children, students, and adults attended?
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Ответ:
182 children, 91 adults, 60 students
Step-by-step explanation:
The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422
12x+ 7(333-3x)+10x=2422
12x+2331-21x+10x=2422
2331+x=2422
x=91- the amount of adults
1) 91*2=182- the amount of children
333-91-182= 60- the amount of students
Ответ:
Since the question is indicating to use a graphing calculator, we can assume that we would be required to graph both of the equations.
Red =![\sqrt{x+2}](/tpl/images/0771/2009/cddc2.png)
Blue =![3x^2-4x-1](/tpl/images/0771/2009/78151.png)
By graphing those equations, we can determine the solution(s)
The points where the graphs intersect would be your coordinates to derive your solution
Red = (1.864, 1.966)
Blue = (-0.427, 1.254)
The solutions would be the x-value of the ordered pair, in this case,
x = 1.864 AND x = -0.427