A multiple choice exam has 20 questions. Each question has 3 possible answers; there is no partial credit. Only 1 answer out of the 3 possible answers is correct; no questions are dependent on getting the correct answer for a previous question. The passing score for the exam is 60% or better. If you randomly guess the answer to each question, what is the probability that you will pass the test? Round your answer to three decimal places and report as a DECIMAL - example: 0.234

To find out the theoretical probability of the case given, we need to make certain assumptions.

First, we'll assume that he'll attempt all of the questions, i.e he'll attempt all 10 questions.

Next assumption is that each option in each question is equally likely to be marked by the student.

This pretty much leads us to a binomial probability distribution.

Conditions are:

   Answers 10 questions.

   Each question has 4 options with only one correct answer and all other incorrect answers.

   Student is equally likely to pick any outcome in any given question.

   Hence, probability of choosing correct answer is 1/4 = 0.25. Probability of choosing incorrect answer is 1–1/4 = 3/4 = 0.75.

   The number of trials is 10.

   Total number of success is exactly 8 and failure is 2 amongst the 10 questions in any particular order.

Now, calculation is fairly simple.

Binomial probability distribution is such that…

P(8 correct ; 2 wrong)

= 10C8 × (0.25)^8 × (0.75)²

= 405/1048576 ≈ 3.862380981 × 10^-4 ≈ 0.000386

Step-by-step explanation:

The graph means that the output is constant and independent on the input which means whatever the input, the output will be the same. 

Mathematically:
The equation of the line is y=4 ie. y= constant and independent on x