A number is chosen at random from the set of consecutive natural numbers $\{1, 2, 3, \ldots, 24\}$. What is the probability that the number chosen is a factor of $4!$? Express your answer as a common fraction.

Step-by-step explanation:

Given

Required

Determine the probability of selecting a factor of 4!

First, we have to calculate 4!

Then, we list set of all factors of 24

The probability of selecting a factor if 24 is calculated as:

Substitute values for n(Set) and n(Factors)

Simplify to lowest term

1. 35.50 increase 60% =

35.50 × (1 + 60%) = 35.50 × (1 + 0.6) = $56.80

2. 14.75 increase 45% =

14.75 × (1 + 45%) = 14.75 × (1 + 0.45) = 21.3875 = $21.39

3. 98.25 increase 7% =

98.25 × (1 + 7%) = 98.25 × (1 + 0.07) = 105.1275 = $105.13

4. 19250.95 increase 4.5% =

19250.95 × (1 + 4.5%) = 19250.95 × (1 + 0.045) = 20117.24275 = $20117.24