donald1255
03.04.2021 •
Mathematics
A parabola opening up or down has vertex (0,3) and passes through (
–
12,15). Write its equation in vertex form.
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Ответ:
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
a²/bc+b²/ca+c²/ab=3.
hence proved