A piece of wire that is 42 meters long is bent into the shape of a rectangle whose length is twice its width. Find the length of the rectangle.

As below

Step-by-step explanation:

the perimeter of our rectangle is 42 meters

and Length is 2 times the width. that is L= 2W

since there are 2 of the Length and Width sides..

42 = 2(L) +2(W)

42= 2(2W) + 2W

42 = 4W + 2W

42 = 6W

W = 42/6

W = 7

now that we know W plug it into our 1st equation

L = 2 (7)

L = 14

Length = 14

width = 7    

:)

So i did this in like 4th grade its easy so basically its A=3 to the 4 power then 4÷7=X but i figured out X its 0.7y=x