A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbits. Create a clear and properly labeled graph of R(t) on the domain 0 ≤ t ≤ 15 months. Required:
a. Find ΔR on [1,2].
b. Find R(0).
c. Find R(10)
d. When will the population be 500 rabbits?

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

R(2) =

40

Difference of rabbits between first and second months is 40.

b. R(0) = 100()

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) =

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

t = 12.5

In 12 and half months, population of rabbits will be 500.

The First answer is

VWXZ+VWXY+WYZ+VXY+VWZ+XYZ

The second possible answer is:

VWXZ+VWYZ+WYZ+VXY+VWZ+XYZ

Step-by-step explanation:

First we draw the k-maps for the function . There are two k-maps, one with V as zero while the other is V as 1. Then we combine the entries in power of 2. Remember that the function is given in maxterms form.Max-terms are those whose value is 0. So all the values other than max-values are either 1 or don't care. So we will keep these terms 0 and other as 1. The k-maps are attached in the files below. The essential prime implicants are those which are repeated in all the possible solutions.In this case Essential prime implicants are :

VWXZ+WYZ+VXY+VWZ+XYZ

http://www.32x8.com/sop5A-B-C-D-Em_4-5-7-8-10-14-15-16-17-18-21-22-23-31d_1-2-12-13option-0899788976571894282724?fbclid=IwAR2BaNgaMe0FXK1AEcwzLb1tkw5Oo-DIn-w0QNxE6ck9nYOSS1GnGtWC4SU