arieannaensley0616

13.08.2020 • 

Mathematics

A professional basketball star who had a reputation for being a poor free throw shooter made 5160 of the 9809 free throws that he attempted, for a success ratio of 0.526. A simulation was developed to generate random numbers between 1 and 1000. An outcome of 1 through 526 was considered to be a free throw that is made, and an outcome of 527 through 1000 was considered to be a free throw that is missed. The list below shows the results for five generated numbers where 1 represents a free throw that was made and 0 represents a free throw that was missed. Complete parts (a) and (b). 0 0 1 1 0
(a) Is the proportion of successful free throws P from the simulation reasonably close to the value of 0.531?
A. Yes. P is reasonably close to the value of 0.531.
B. No. P is not reasonably close to the value of 0.531.
(b) The simulation was conducted 10 times to generate five results R1. R2. R3. R4 and R5 each time, as shown in the table below. Determine the proportion of successful free throws P in each case.
Case R1 R2 R3 R4 R5 P
1 0 0 1 1 0
2 0 1 0 1 0
3 1 1 0 1 0
4 1 1 1 0 0
5 0 1 0 0 0
6 1 0 0 0 0
7 0 0 0 0 0
8 0 0 0 0 0
9 1 1 0 1 1
10 0 1 1 0 1
(Do not round)
(c) Based on the above results, would it be unusual for the professional basketball star to make all of five free throws in a game?
A. Yes
B. Nο

Ответ:

harleycochran2ovyt3n

03.01.2022

Mathematics

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Complete question :

Edward bought 3 packages of hot dogs with 8 hot dogs in each package.He also bought 3 bags of hot dog buns 4 in each bag. Six people were hving lunch at his home, including eddward.How many hot dogs with bns could each of them have>

4 hot dogs and 2 hot dog buns each

Step-by-step explanation:

Number of packages = 3

Number of hotdog package = 8

Total number of hotdogs = 8 * 3 = 24

Hot dog buns = 4 per bag

Buns = 4 * 3 = 12 buns

Hence the 6 could each have :

Hotdogs = 24 /6 = 4

Buns = 12 /6 = 2

4 hot dogs and 2 hot dog buns each

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