valeriegarcia12
30.11.2021 •
Mathematics
A random sample of 100 observations from a population with standard deviation 20.01 yielded a sample mean of 93.5. 1. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ>90 using α=.05, find the following:
t-test value:
p sample
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Ответ:
\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}
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