Mathematics: A random sample of 130 students is chosen from a population of 4,500 students. The mean IQ in the sample is 120, with a standard deviation of 5. Using a margin of error of 1.13%, what is the 99% confidence interval for the students mean IQ score?

A random sample of 130 students is chosen from a - id1306961702, sierravick123owr441

Ответ:

charliesteioff14

29.01.2022

Mathematics

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

Step-by-step explanation:

Information given

$\bar X= 120$ represent the sample mean

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=130 represent the sample size

For this case we can't set a margin of error just with a % since they not specify 1.13% respect to something for this case we can omit this value

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

df=n-1=130-1=129

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , and the critical value would be $t_{\alpha/2}=2.614$

And replacing we got:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

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Ответ:

brebun4742

28.08.2020

Mathematics

answer:

8$?

Step-by-step explanation:

Well the question didn't say anything of how much Nancy is selling to people and the exact amount of items she sells.

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A random sample of 130 students is chosen from a population of 4,500 students. The mean IQ in the sample is 120, with a standard deviation of 5. Using a margin of error of 1.13%, what is the 99% confidence interval for the students' mean IQ score?

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