A rectangle has an area of 135 square meters and has a width that is 6 meters shorter than its length what is the perimeter of the rectangle

Step-by-step explanation:

length = x m

Width = (x - 6) m

Area = 135 sq.m

length * width = 135

x*(x-6) = 135

x*x - x*6 -135 = 0

x²-  6x - 135 = 0

x² - 15x + 9x - 9*15 = 0

x(x - 15) + 9(x-15) = 0

(x-15)(x + 9) = 0

x - 15 = 0  

{x+9=0 is ignored because measurement cannot be a negative number}

x= 15

length = 15 m

width = x - 6 = 15 - 6 = 9 m

Perimeter = 2*(length + width)

                 = 2*(15 + 9) = 2 * 24 = 48 m

AB=DC

Step-by-step explanation: