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karennayeli
10.03.2020 •
Mathematics
A rectangle is 2m long. It’s diagonal is 3m long. Work out the width of the rectangle, to the nearest cm
Pls answer quickly
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Ответ:
To the nearest cm
Width of the rectangle = 224cm
Step-by-step explanation:
Imagine a rectangle shape,
both opposite sides are equal, ie both lengths are equal and also applicable to the widths
Length is 2m
It's diagonal is 3m
The diagonal is a line that crosses from one length of a side to the other slantly, ie from one edge to the other, dividing the rectangle into two right angled triangles
The longest line will be the diagonal which is 3m
And the base length will be the length which is 2m
The width is what we are looking for which is represented with x
To solve this problem, we use Pythagoras' rule
x^2 = a^2 + b^2
Let x be diagonal side
a be length
b be the unknown width
Inserting into the formula
x^2 = a^2 + b^2
3^2 = 2^2 + b^2
9 = 4 + b^2
9 - 4 = b^2
5 = b^2
Square root of 5
b = 2.24m
The width = 2.24m
According to the question, we are asked to give the answer in nearest cm
Since 1cm = 0.01m
x cm = 2.24m
Then we cross multiply
1cm * 2.24m = xcm * 0.01m
x = 2.24 / 0.01
x = 224cm
Ответ:
blue because it has 2 vowels
Step-by-step explanation:
A is a vowel E is also one I,O,U are also vowels. U and E are both in the word blue and 1+1=2 therefore 2 vowels being in the word blue and 1+1=2 means B is the answer.