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astepania0003
29.10.2020 •
Mathematics
A rectangle whose area is 336 square feet has a length that is 4 meters less than the twice the width. Find the dimensions of the rectangle.
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Ответ:
L = 2(16.675) - 13.2 = 20.15 ft
W = 16.675 ft
Solution
width = x
length = 2x - 4m
m = 3.3 ft
Area = W × L = 336 ft^2
(2x - 4(3.3)) × x = 336 ft^2
solve for x
2x^2 - 13.2x = 336 ft^2
quadratic equation reveals 2 X's
x = -10.075, 16.675
a distance can't be a negative so...
x = 16.675 ft
L = 2(16.675) - 13.2 = 20.15 ft
W = 16.675 ft
Ответ: