A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm. What is the approximate area of the triangle? Round to the nearest tenth.

Area of a triangle = One-1/2bh

161.8cm²

Step-by-step explanation:

solve for height which is the opposite

opp=x

sin(theata)= opp./hyp.

sin23=x/30

x=30×sin23

x=11.72cm

height=opposite

height=11.72cm

base=adjacent

base=27.6cm

½of 27.6cm=13.8

13.8cm×11.72cm=161.74 (2d.p)

161.74 rounded to the nearest tenths= 161.7

I'm not sure if it's the answer but it's the closest thing to the options

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