A robot has a straight arm 20 inches long that can rotate about the origin of a coordinate system. If the robot’s hand is located at (-20,0) and then rotates through an angle of 45°, what is the new location of the hand with the coordinates approximated to the nearest 0.01 inch?

The location of the robots hand after rotating 45° counterclockwise from (-20, 0) in inches is (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0)) in inches is (-14.14, -14.14)

Step-by-step explanation:

The initial location of the robots hand = (-20, 0)

The angle through which the robot rotates his hand = 45°

∴ We have the length of the robots hand = 20 inches

We note that (-20, 0) is in the 2nd Quadrant

The location of the robots hand after rotating 45° counterclockwise = 135°

Therefore, the location of the robots hand after the rotation = (20×cos(135°), 20×sin(135°)) = (-10·√2, 10·√2) = (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0) = 225°

Therefore, the location of the robots hand after the rotation = (20×cos(225°), 20×sin(225°)) = (-10·√2, -10·√2) = (-14.14, -14.14)

( solution at pic)