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hellicuh
17.06.2021 •
Mathematics
A shop that sells nuts has one mixture that is 30% pecans and 70% peanuts. A second mixture is 40% pecans and 60% peanuts. The manager wants to make a mixture that is 38% pecans. She wants to use 25 ounces more of the second mixture than of the first. How many ounces of each mixture should she use
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Ответ:
Ответ:
=> x = 8.33 oz weight of the first mixture therefore weight of the second mixture would be:
x+25= 8.33+25=33.33 oz
Step-by-step explanation:
We want to find the weight of each mixture which are unknown to us right now, therefore:
Let the weight of the first mixture be x. Then the weight of the second mixture would be (x+25) and the weight of final mixture would be (x + x + 25) = 2x+25.
The first mixture had 30% pecans, therefore the weight of pecans from the first mixture would be 0.3x.
The second mixture had 40% pecans, therefore the weight of pecans from the second mixture would be 0.4 * (x+25).
We will have 38% pecans in the final mixture hence the weight of pecans is 0.38 of the total weight of pecans in the final mixture.
0.38 * (2x + 25)
Therefore
0.38 * (2x + 25) = 0.3x + 0.4*(x + 25).
Now we have one equation one unknown and solve for x:
=> 0.76x + 9.5 = 0.7x + 10
=> 0.76x - 0.7x = 10 - 9.5
=> 0.06x = 0.5
=> x = 50/0.06
=> x = 50/6 = 25/3
=> x = 8.33 oz weight of the first mixture therefore weight of the second mixture would be:
x+25= 8.33+25=33.33 oz
Ответ: