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mai1261
03.11.2020 •
Mathematics
A simple random sample of 40 colleges and universities in the United States has a mean tuition of 19,300 with a standard deviation of 10,600. Construct a 95% confidence interval for the mean tuition for all colleges and universities in the United States. Round the answers to the nearest whole numb
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Ответ:
16,015≤x≤22,585
Step-by-step explanation:
Formula for calculating the confidence interval is expressed as:
CI = xbar ± z *(s/√n) where;
xbar is the mean tuition = 19,300
s is the standard deviation = 10,600
n is the sample size = 40
z is the z-score at 95% confidence interval = 1.960
Substitute the values into the equation
CI = 19300 ± (1.960) *(10,600/√40)
CI = 19300± (1.960) *(10,600/6.325)
CI = 19300± (1.960) *(1,675.889)
CI = 19300±3,284.743
CI = [19300-3,284.743, 19300+3,284.743]
CI = [16,015.257, 22584.74]
CI = [16,015, 22585] (to nearest whole number)
Hence a 95% confidence interval for the mean tuition for all colleges and universities in the United States is 16,015≤x≤22,585
Ответ:
Step by step
If he made 30 smoothies today then then yesterday he had 50 % of today’s that half so 30 % 15 = 2