A single 6 side die is 'rolled twice. There are 36 equally likely outcomes. Find the probability of getting two numbers whose sum is
8.The probability of getting two numbers whose sum is 8 is

Your first answer is in picture:8. The possible outcomes when two dice are thrown together are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

Therefore, probability P of getting a sum equal to 8 is:

P= 36/5

Hence, the probability of getting a sum equal to 8 is 36/5 .

Step-by-step explanation:

Hope it is helpful...

The answer is

The first zero after the decimal is the tenths place, the second zero is the hundredths place, the third zero is the thousandths place, and of course the five is in the ten thousandths place

The reason why its not a whole number is because when there is a whole number with a decimal, there is a word that separates a whole number with the decimals such as the words "and" or "point".

But instead you said it in word expanded form which is equivalent to ⇒ .0005