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Lovemimi4129
16.04.2020 •
Mathematics
A stop sign is a regular octagon. The standard stop sign has a 16.2 inch radius. The area of a standard stop sign is
square inches. Please round your answer to the nearest whole number
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Ответ:
The area of standard stop sign regular octagon is 742.3 squared inches, if the standard stop sign has a 16.2 inch radius.
Step-by-step explanation:
The given is,
Radius of standard stop sign is 16.2 inch radius
Step:1
The regular octagon is equal to the 16 right angled triangle,
Angle of right angle triangle =
= 22.5°
Ref attachment,
From the OAB right angle triangle,
Trigonometric ratio,
sin ∅ =
Where, ∅ = 22.5°
Hyp = Radius = 16.2 inches
Ratio becomes,
sin 22.5°=![\frac{b}{16.2}](/tpl/images/0605/5235/d7a4c.png)
b = (0.374607)(16.2)
b = 6.19947 inches
Trigonometric ratio,
cos ∅ =
Where, ∅ = 22.5°
Hyp = Radius = 16.2 inches
Adj = h
Ratio becomes,
cos 22.5°=![\frac{h}{16.2}](/tpl/images/0605/5235/ff0d9.png)
h = (0.9238795)(16.2)
h = 14.967 inches
Step:2
From the triangle OAC,
Area,![A = \frac{1}{2} (Height )( Base)](/tpl/images/0605/5235/4fd41.png)
Where, Height = 14.967 inches
Base = b + x = 6.19947 + 6.19947
= 12.3989 inches
From the values equation becomes,
A =![\frac{1}{2} (14.967)(12.39894)](/tpl/images/0605/5235/fe2ef.png)
A = 92.7875 Squared inches
Step:3
The octagon is equal to sum of 8 triangles
Area of octagon = 8 × Area of triangle
= 8 × 92.7875
= 742.3 squared inches
Result:
The area of standard stop sign regular octagon is 742.3 squared inches, if the standard stop sign has a 16.2 inch radius.
Ответ:
Step-by-step explanation:
using Pythagoras theorem adjacent will be 15
so cos will be adjacent/hypotenuse
which is 15/17=0.882