A student is taking two courses, history and math. The probability the student will pass the history course is 0.79, and the probability of passing the math course is 0.68. The probability of passing both is 0.57. What is the probability of passing at least one? (Round to two decimal places as needed).

0.97 = 97%

Step-by-step explanation:

The probability of passing at least one is the sum of:

probability of passing history and not passing math,

probability of passing math and not passing history,

probability of passing both of them.

The first one is 0.79 * (1-0.68) = 0.79 * 0.32 = 0.2528

The second one is 0.68 * (1-0.79) = 0.68 * 0.21 = 0.1428

The third one is 0.57.

So, the probability of passing at least one is:

0.2528 + 0.1428 + 0.57 = 0.9656

rouding to two decimal plates, we have 0.97 = 97%

· Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-18x' to each side of the equation.-6 + 6x + -18x = 18x + -18x. Combine like terms: 6x + -18x = -12x-6 + -12x = 18x + -18x. Combine like terms: 18x + -18x = 0-6 + -12x = 0. Add '6' to each side of the equation.-6 + 6 + -12x = 0 + 6. Combine .

Step-by-step explanation: