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bgallman153p71edg
15.07.2020 •
Mathematics
A superintendent of a school district conducted a survey to find out the level of job satisfaction among teachers. Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.
z equals fraction numerator p with hat on top minus p over denominator square root of begin display style fraction numerator p q over denominator n end fraction end style end root end fraction
The superintendent wishes to construct a significance test for her data. She find that the proportion of satisfied teachers nationally is 18.4%.
What is the z-statistic for this data? Answer choices are rounded to the hundredths place.
a. 2.90
b. 1.15
c. 1.24
d. 0.61
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Ответ:
b. 1.15
Step-by-step explanation:
The z statistics is given by:
In which X is the found proportion, p is the expected proportion, and s, which is the standard error is![s = \sqrt{\frac{p(1-p)}{n}}](/tpl/images/0706/8425/73804.png)
Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.
This means that![X = \frac{13}{53} = 0.2453](/tpl/images/0706/8425/9bf15.png)
She find that the proportion of satisfied teachers nationally is 18.4%.
This means that![p = 0.184](/tpl/images/0706/8425/06561.png)
Standard error:
p = 0.184, n = 53.
So
Z-statistic:
The correct answer is:
b. 1.15
Ответ:
00
step-by-step explanation: