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desstinee863
02.11.2020 •
Mathematics
A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of milligrams and a standard deviation of milligrams. What is the probability that randomly selected light cigarettes from this company will have a total combined nicotine content of milligrams or less, assuming the company's claims to be true? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.
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Ответ:
The missing values in the given question is shown below.
A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of 1.5 milligrams and a standard deviation of 0.52 milligrams. What is the probability that 50 randomly selected light cigarettes from this company will have a total combined nicotine content of 81 milligrams or less, assuming the company's claims to be true? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.
P(x ≤ 1.62) = 0.949 to three decimal places.
Step-by-step explanation:
From the question; given that:
The population mean = 1.5
The standard deviation = 0.52
The sample size n = 50
The sample mean
= 1.62
Hence; we can calculate the required probability as:
From z - tables;
P(x ≤ 1.62) = 0.9486
P(x ≤ 1.62) = 0.949 to three decimal places.
Ответ:
C
Step-by-step explanation:
No, because for two triangles to be similar, the angles must be the exact same.