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Baby010391
08.03.2020 •
Mathematics
A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base and height of the triangle
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Ответ:
The base of triangle is
and the height of triangle is ![\frac{12}{\sqrt{3}} \ m.](/tpl/images/0538/3428/af141.png)
Step-by-step explanation:
Given:
A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.
Now, to find the base and height of the triangle.
The base of triangle =![x\times\frac{1}{2} =\frac{x}{2} \ m.](/tpl/images/0538/3428/25047.png)
The height of triangle =![x\times \frac{3}{4} =\frac{3x}{4}\ m.](/tpl/images/0538/3428/ce796.png)
The area of triangle =![16\ m^2.](/tpl/images/0538/3428/e59a9.png)
Now, we put the formula of area to solve:
Multiplying both sides by 16 we get:
Dividing both sides by 3 we get:
Using square root on both sides we get:
Now, by substituting the value of
to get the base and height:
So, the base of triangle =![\frac{8}{\sqrt{3}} \ m.](/tpl/images/0538/3428/54c76.png)
Thus, the height of triangle =![\frac{12}{\sqrt{3}} \ m.](/tpl/images/0538/3428/af141.png)
Therefore, the base of triangle is
and the height of triangle is ![\frac{12}{\sqrt{3}} \ m.](/tpl/images/0538/3428/af141.png)
Ответ:
z/5 = 6
z=30
Step-by-step explanation:
you need 6 so 30 divided by 5 equals 6 so 6-7=-1