anonymousanon
26.03.2020 •
Mathematics
A woman is 4 times as old as her son.9 years ago,the sum of their ages was 42.Find their present ages
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Ответ:
36 years
Step-by-step explanation:
Let
Daughter = x
Mother = 3*x = 3x
6years ago? Daughter = x-6
Mother = 3x-6
Sum of ages at this time = (x-6) + (3x-6) = 36
x - 6 + 3x - 6 = 36
4x +(-12) = 36
4x = 36 + 12
4x = 48
x = 48/4 ; 12 years old.
Mother = 12*3= 36 years old.
Check. 12–6= 6;
36–6=30
30+6=36 years.
Ответ:
Step-by-step explanation: