Aball is thrown into the air with an upward velocity of 36 ft/s. its height h in feet after t seconds is given by the function h = −16t2 + 36t + 9. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ball’s maximum height?

a. 1.13 s; 69.75 ft

b.1.13 s; 29.25 ft

c.2.25 s; 9 ft

d.1.13 s; 31.5 ft

 B) 1.13 s; 29.25 ft

Step-by-step explanation:

Height of the ball h in feet after t seconds is given by the function

Now at maximum height

=>

After rounding to nearest hundredth,

Height ,

Therefore , t=1.13 s and  

Thus correct option is B) 1.13 s; 29.25 ft

the expression looks like its missing the x value tbh...

you provided x and y but the expression doesn't

have an x.

so, that applied, 4.02+3(6)

4.02+3(6)

4.02+18

22.02

but if you wrote your expression wrong and you meant to write 4.02x+3y,

than:

4.02(5) + 3(6)

20.1+18

= 38.1

So, if you actually meant 4.02 + 3y, ur answer would be 22.02, but if you meant 4.02x+3y, then your answer would be 38.1