Aball is thrown straight up from the top of a building 132 ft. tall with an initial velocity of 48 ft per second. the distance s(t) (in feet) of the ball from the ground is given by s(t) = 132 + 48t − 16t2. find the maximum height attained by the ball.

The line of symmetry through the parabola described by s(t) is

... t = -48/(2×(-16)) = 1.5

This is the time at which the ball reaches its maximum height.

... s(1.5) = 132 + 48×1.5 -16×1.5²

... s(1.5) = 132 + 72 - 36 = 168

The maximum height attained by the ball is 168 ft.

check the picture below.

so the maximum height of the ball is obtained at the vertex's y-coordinate, hmm what is it anyway?

The answer would be 7%