aaliyahmaile13

01.01.2020 • 

Mathematics

Abasketball is thrown with an initial upward velocity of 25 feet per second from a height of 8 feet above the ground. the equation h=-16t^2+25t+8 models the height in feet t seconds after it is thrown. after the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground. about how long after it was thrown does it go into the hoop?

Ответ:

zahriamarie10

14.01.2022

Mathematics

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So we want to know the later time when h=10 so

10=-16t^2+25t+8

16t^2-25t+2=0

Using the quadratic formula for expediency...

t=(25±√497)/32, we want the time when it was falling so

t=(25+√497)/32

t≈1.48 seconds (to nearest hundredth of a second)

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Ответ:

monica1670

24.03.2021

Mathematics

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B.     1.8 x 10⁴

Step-by-step explanation:

6.3 / 3.5 = 1.8

10⁷/ 10³ = 10⁴

Therefor

6.3 x 10⁷ / 3.5 x 10³ = 1.8 x 10⁴

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