ABCD is a parallelogram. Given that,
DC = CE
prove that,
area of the ADE triangle is equal to the area of the parallelogram.

need explanation

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Step-by-step explanation:

We khow that ABCD is a parallelogram so its area is the product of the base (DC) and the the height

Let H be the height of the paralellogram and A its area So A= DC*H

ADE is a triangle . Its area is the product of the height and the base(DE) over 2

We notice that the paralellogram and the triangle have both the same height Let S be the area of the triangle S= (DE*H)/2= DE/2 *H = DC *H

So the triangle and the parallelogram have the same area

The solution is 12. The equation is (115 - 19) ÷ 8.

Step-by-step explanation:

We can solve this problem by using division.

First, let's take away 19.

115 - 19 = 96

Now let's divide 96 by 8.

96 ÷ 8 = 12.

And we have 12, our answer.