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carleenespriu
17.07.2020 •
Mathematics
ABCD is a quadrilateral inscribed in a circle, as shown below: Circle O is shown with a quadrilateral ABCD inscribed inside it.
Angle A is labeled x plus 16. Angle B is labeled x degrees. Angle C is labeled 6x minus 4. Angle D is labeled 2x plus 16.
What equation can be used to solve for angle B?
(x + 16) − (6x − 4) = 180
(x + 16) + (x) = 90
(2x + 16) + (x) = 180
(x + 16) − (x) = 90
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Ответ:
C. (2x + 16) + (x) = 180°
Step-by-step explanation:
See attachment for the cyclic quadrilateral
One theorem of cyclic quadrilateral states that; opposite angles = 180°
In the attachment, the angle opposite B is D
Where B = x
D = 2x + 16
From the theorem stated above;
B + D = 180°
Substitute the values of B and D in the formula above
x + 2x + 16 = 180
From the list of given options, the correct answer is C
Ответ:
Step-by-step explanation:
6 is one integer it says more than another so u double 6 which is 36
6 times 36=216
Hope this helps