kaylaamberd
02.08.2019 •
Mathematics
Abcd rhombus, ac: bd = 4: 3 perimeter abcd = 20 cm find: area of abcd
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Ответ:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
Ответ:
A leg
Step-by-step explanation:
The hypotenuse is the longest leg of a triangle, and the hypotenuse is across the greatest angle, which is the 90 degree angle in this case. Thus, side "a" is a leg.