Abox is launched upward from the ground at a speed of 57 feet per second. calculate the height in feet of the box at 3 seconds. use g=32 ft/s^2 as the acceleration due to gravity

The vertical height traveled is given by
h = ut +- (1/2)g*t^2
where 
u = 57 ft/s, initial speed
t = tme, s
g = 32 ft/s^2

After 3 seconds,
h = (57 ft/s)*(3 s) - (1/2)*(32 ft/s^2)*(3 s)^2
   = 171 - 144
   = 27 ft

 27 ft

Part B Which passage from the selection best supports the answer to Part A (question 1)?

Question 2 options:

“I’m very sorry, Lady, … ” whispered the boy.

“There’s nobody home at my house,” said the boy.

“You gonna take me to jail?” asked the boy.…

“Do you need somebody to go to the store,” asked the boy.

Step-by-step explanation: