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aliviafrancois2000
06.10.2019 •
Mathematics
Abuilding lot in a city is shaped as a 30°-60°-90° triangle, like the figure shown.
the side opposite the 30° angle measures 41 feet.
a) find the length of the side of the lot opposite the 60° angle.(show how i know).
b) find the length of the hypotenuse of the triangular lot.(show how i know)
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Ответ:
Tan(α)=Opposite/Adjacent
α=60°
Opposite=41 feet
Adjacent=x
When you substitute these values into Tan(α)=Opposite/Adjacent, you obtain:
Tan(60°)=x/41
(41)Tan(60°)=x
x=41√3
x=71.01 feet
B) Now, you can find the length of the hypotenuse:
Cos(α)=Adjacent/Hypotenuse
α=60°
Adjacent=41 feet
Hypotenuse=y
When you substitute these values into Cos(α)=Adjacent/Hypotenuse, you obtain:
Cos(60°)=41/y
yCos(60°)=41
y=41/Cos(60°)
y=82 feet
Ответ:
Ответ:
the answer for the expression is 384