उक्त समयमा बसले कति दुरी पार गर्दछ ? Abusstarts from rest. If the acceleration of the bus is 0.5m/s, what will be it's
ve ocity at the end of 2 minutes and what distance will it cover
during that time?

The magnitude of the velocity will be 60 m/s.

The distance covered is 3,600 m

Step-by-step explanation:

Constant Acceleration Motion

It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:

The distance traveled by the object is calculated as:

The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:

The magnitude of the velocity will be 60 m/s.

The distance covered during that time is:

x = 3,600 m

The distance covered is 3,600 m

30

Step-by-step explanation:

this is a right-angled triangle.

as we can see on the graph and the coordinate units,

AB = 4

BC = 7

=>

AC² = AB² + BC² = 4² + 7² = 16+49 = 65

AC = sqrt(65)

now, in every triangle there are certain ratios equal to each other.

a/sin(A) = b/sin(B) = c/sin(C)

a is here BC

b is here AC

c is here AB

and we know B = 90 degrees

sin(90) = 1

so, we have

sqrt(65)/1 = 4/sin(C)

sqrt(65) = 4/sin(C)

sin(C) = 4/sqrt(65) = 0.496138938...

C = 29.7448813...

the closest answer option is 30.