AC = 3x + 3, BC = 12, and AB = x + 5. Find AC

As, We're given with,

AB = x + 5, BC = 12, AC = 3x + 3

By segment addition postulate,

⇒AB + BC = AC

⇒x + 5 + 12 = 3x + 3

⇒5 + 12 - 3 = 3x - x

⇒17 - 3 = 2x

⇒14 = 2x

⇒2x = 14

⇒ x = 14/2

⇒ x = 7

Now, finding the measure of AC,

⇒Measure of AC = 3x + 3

= 3(7)+ 3

= 3 × 7 + 3

= 21 + 3

= 24

∴ The measure of AC is 24 ...!

AC = 24

Step-by-step explanation:

Collinear points all lie on the same line, so point A, B, and C are on one line.

So, Ab + BC = AC

AB + BC = AC

x + 5 + 12 = 3x + 3

x + 17 = 3x + 3

   -3             -3

x + 14 = 3x

-x          -x

14 = 2x

/2     /2

7 = x

AC = 3x + 3

= 3 (7) + 3

= 21 + 3

= 24

AC = 24

The line crosses the y and x-axis at (0, 1) and (-4, 0) respectively.

Step-by-step explanation: