Acampground owner plans to enclose a rectangular field adjacent to a river. the owner wants the field to contain 180,000 square meters. no fencing is required along the river. what dimensions will use the least amount of fencing?

Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of . 
The area is the product between the two sizes:
(1)
While the perimeter is twice the sum of the two sizes:
(2)

From (1) we can write

and we can substitute it into (2):


To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:

The derivative of the perimeter is

If we require p'(x)=0, we find


And the other side is


This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.

It should be 57.6 minutes.

Step-by-step explanation:

Because if you divide 24 by 15 you get 1.6 and 1.6 times 36 is 57.6