Acandy necklace is extended from the top of a 10-foot ice cream cone to the ground. the necklace makes a 55 degree angle of the ice cream cone. how long is the necklace?

The length of the necklace is 12.20 foot

Step-by-step explanation:

Given as :

The height of the ice cream cone to the ground = h = 10 foot

The angle make by the necklace of the ice cream cone = 55°

Let The length of the necklace = L foot

Now, from figure

Height = BC = h foot

The length of the necklace = L = AC

So, Sin angle =

Or, Sin 55° =

Or, 0.8191 =

Or, 0.8191 =

Or, L =

∴  L = 12.20 foot

So, The length of necklace = L = 12.20 foot

Hence The length of the necklace is 12.20 foot Answer

Check explanation section (check the attached file for the diagram to the question).

Step-by-step explanation:

Without mincing words let's dive straight into the solution to the question/ problem above.

From the question above, we have that the point p = the point at which the bisecting angle of the triangles meets, that is the term known as incenter.

So, we have that; 7x - 6 = 5x + 4. Hence;

2x = 10; x = 5°.  

Thus, the angle 5x + 4 = which is the angle KJP = 5x + 4. Recall from above that x = 5°.

Hence; 5x + 4 = 5(5) + 4 = 25 - 4 = 29°.

Also, the angle 7x - 6 = which is the angle KJP = 7x - 6. Recall from above that x = 5°.

Therefore, 7x - 6  = 7(5) - 6 = 35 - 6 = 29°.

The angle KJP + the angle LJP= the angle KJL.

Therefore, the angle KJL = 29° + 29° = 58°.

Angle KJL = 130 - ( angle KJL) - (angle KJL).

The angle KJL = 130° - ( 58°) - (52° ) = 70°