Mathematics: Acar starts from start to rest and reaches a speed of 40 m/s in 10 s. if acceleration is constant, how fast wil it be moving in 5 s

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Acar starts from start to rest and reaches a

izearaholland7308

12.01.2022

Car fastly moved in 5s is

${\bf V_{3}} = {\bf 60}\frac{\bf m}{\bf s}$

Step-by-step explanation:

Given that a car starts from start to rest

so $V_{1} = 0$ and $T_{1}=0$

and given car reaches a speed of 40 m/s in 10 s.

ie, $V_{2} =40$ and $T_{2} = 10$

Use the formula

$The rate of change of velocities=acceleration\times the rate of change of times$

ie, $V_{2} - V_{1} = a(T_{2}-T_{1})$

$V_{1} = 0$ , $T_{1} = 0$ and a = constant

So, $a = \frac {V_{2}}{T_{2}}$

$a = \frac {40}{10}$

$a = 4 \frac {m}{s}^{2}$

Similarly,

$T_{3} = 15s$ (5 seconds later) and $V_{1} = 0$ , $T_{1} = 0$

$V_{3} - V_{1} = a\times (T_{3} -T_{1})$

Then $V_{3}-0= 4\times (15-0)$

$V_{3} = 4\times (15)$

$V_{3} = 60\frac {m}{s}$

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