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ewinter13
23.11.2019 •
Mathematics
Acar that originally cost $20,000 depreciates (loses value) by 15% each year. in about how many years will the car be worth half its value? use the equation 10,000 = 20,000(0.85)^x to solve the problem. round your answer to the nearest dollar.
? years
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Ответ:
x = # of years
10,000 = 20,000 (0.85)^x, first divide both sides by 20,000
0.5 = (0.85)^x, next take the ln of both sides
ln 0.5 = ln (0.85)^x, by rules of logarithms you may move x to make it a coefficient of the logarithm
ln 0.5 = x (ln 0.85), divide both sides by ln (0.85)
x = (ln 0.5)/ (ln 0.85) = (-0.693)/(-0.1625) = 4.26 years
Ответ:
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