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yialefi
23.01.2020 •
Mathematics
Acar travels along a straight road for 30 seconds starting at time t = 0. its acceleration in ft/sec2 is given by the linear graph below for the time interval [0, 30]. at t = 0, the velocity of the car is 0 and its position is 10. what is the position of the car when t = 20? you must show your work answer to 3 decimal places. include units in your answer.
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Ответ:
666.667 feet
Step-by-step explanation:
Slope = -1
Intercept = 10
y = -t + 10
y is the acceleration
Integrate y fornv
v = -t²/2 + 10t + c
At t=0, v=0 so c = 0
v = -t²/2 + 10t
Turns when v = 0,
-t²/2 + 10t = 0
t = 0, 20
Integrate v for s
s = -t³/6 + 5t² + c
At t = 0, s = 10
10 = c
s = -t³/6 + 5t² + 10
s at t=30,
-(30³)/6 + 5(30)² + 10
= 10m
(Back to starting point)
At t = 20,
Displacement in
-(20³)/6 + 5(20)² + 10
= 343.333
Total distance = 2(343.333-10)
= 666.6667
Ответ:
x+y=<200
X-number of tickets sold at the door
Y-number of tickets sold in advance