cjulius9437

23.11.2019 • 

Mathematics

Achurch is bringing a group of its members to a "clean comedians" show. if they bring 15 people, it will cost $10 each. for each additional person the church brings, the price per ticket will go down $0.20. groups are limited to 35 people because of the seating capacity of the auditorium.
what will it cost the church to bring 18 members? (round your answer to the nearest cent.)
it costs the church $ to bring 18 members to the "clean comedian" show.
use your model to find the total cost of bringing a group of 26 people. (round your answer to the nearest cent.)
it costs $ bring 26 members to the show.
if the church can only afford to pay $210.80 for this trip, how many people can the church bring? (enter your answers from smallest to largest.)
the church can bring value) value) people to the show for $210.80

Ответ:

danbat3023

30.04.2022

Mathematics

---

answer: answer 80$

step-by-step explanation: step-by-step explanation:

we have been given that david, egil and frances share money in the ratio 2: 7: 9.

let 2x, 7x and 9x be the amounts of money that david, agil and frances get respectively.  

we are told that frances gets $80 more than david. so we can write this information in an equation as:

9x=2x+80

now let us solve for x.

9x-2x=80

7x=80

x=\frac{80}{7}

now let us substitute x=\frac{80}{7} in 7x (amount of money that egil gets).

\text{ amount of money that egil will get}=7\cdot \frac{80}{7}

upon cancelling out 7 from numerator and denominator we will get,

\text{ amount of money that egil will get}=80  

therefore, egil will get $80.    

---

0,0(0 оценок)