Acircle has a radius of square root of 13 units and is centered at (-9.3,4.1) write the equation of this circle. can anyone me with this problem

(x + 9.3)²  +  (y - 4.1)² = 13

which can be further simplified to;

x² + y² + 9.3x  - 4.1 y + 90.3 = 0

Step-by-step explanation:

using the standard equation of a circle

(x-a)²   +  (y-b)²  =  r²

where (a,b) is the center of the circle  and r is the radius of the circle

From the question, the circle is cemtered at (-9.3, 4.1) and the radius is √13

We can now proceed to formth equation of the circle

(x + 9.3)²  +  (y - 4.1)²  =(√13)²

(x + 9.3)²  +  (y - 4.1)² = 13

We can further simplify it,

x² + 9.3x + 86.49  + y² - 4.1y + 16.81  =13

x² + y² + 9.3x  - 4.1 y + 103.3 = 13

x² + y² + 9.3x  - 4.1 y + 103.3 - 13 = 0

x² + y² + 9.3x  - 4.1 y + 90.3 = 0

Sure?

Step-by-step explanation: