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rydro6019
04.08.2019 •
Mathematics
Acircle is centered at the point (5,-4) and passes through (-3,2). the equation of this circle is (x+²+(y+²=
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Ответ:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)^2 + (y-(-4))^2 = r^2
(x-5)^2 + (y+4)^2 = r^2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))^2+((-4)-2)^2]^1/2
r = [8^2 + (-6)^2]^1/2
r = [64 + 36]^1/2
r = 100^1/2
r= 10
The final equation is:
(x-5)^2 + (y+4)^2 = 10^2
Ответ:
-5.2, -4 8.11, -4.625, -4 4.5
Step-by-step explanation: