Naysa150724
22.08.2019 •
Mathematics
Acircle is inside a square. the radius of the circle is increasing at a rate of 4 meters per day and the sides of the square are increasing at a rate of 3 meters per day. when the radius is 3 meters, and the sides are 20 meters, then how fast is the area outside the circle but inside the square changing?
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Ответ:
The area is changing by the rate of 44.62 meters per sec.
Step-by-step explanation:
Let x be the side of the square and r be the radius of the circle,
Then, the area outside the circle but inside the square is,
V = Area of square - area of circle,
∵ Area of a square = side² and area of a circle = (radius)²,
Thus,
Differentiating with respect to t ( time )
We have,
x = 20 meters, r = 3 meters,
Ответ:
3x=-5 (subtract 5 both sides)
X=. -5/3 (divide both sides by 3)
C. A+x = b
X = b-a (just get x alone)
D. Cx = d
X = d/c