Acircle with area 9π has a sector with a central angle of 1/9 π radians . what is the area of the sector? answer worth 50

A = pi/2

Step-by-step explanation:

Area of a sector is given by

A = 1/2 r^2 theta when theta is given in radians

We know the area of the circle (pi * r^2) so we multiply by pi/pi

A = 1/2  pi/pi r^2 theta

A = 1/(2* pi)  * pi r^2 theta  

   =  1/(2* pi)  * Ac theta   where Ac is the area of a circle

Substituting what we know  Ac = 9 pi and theta = 1/9 * pi

A    =  1/(2* pi)  * 9*pi  1/9 * pi

A = 1/(2* pi)  * pi^2

A = 1/2 * pi

A = pi/2

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Step-by-step explanation:

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Step-by-step explanation:

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